Calculo de un circuito de doble polaridad de la forma:

$$f(t)=t , -2 \leq t \leq 2$$

Serie Trigonométrica de Fourier:

$$f(t)= \frac{a_{0}}{2} + \displaystyle\sum_{n=1}^\infty a_{n}\cos{n\omega_{0}t} + b_{n}\sin{n\omega_{0}t}$$

Serie Compleja de Fourier:

$$f(t)= C_{0} + \sum_{\substack{n=-\infty\\n\ne 0}}^\infty C_{n}e^{in\omega_{0}t}$$
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$$T=4$$ $$\omega_{0}= \frac{2\pi}{T}=2\pi f=\frac{2\pi}{4}=\frac{\pi}{2}$$ $$f=\frac{1}{T}=\frac{\omega_{0}}{2\pi}=\frac{1}{4}=\cfrac{\cfrac{\pi}{2}}{\cfrac{2\pi}{1}}=\frac{\pi}{4\pi}=\frac{1}{4}$$

Coeficientes de Fourier para Serie Trigonometrica:

$$a_{0}= \frac{2}{T} \int_{d}^{d+T}f(t) \, dt$$ $$a_{n} = \frac{2}{T} \int_{d}^{d+T} f(t) \cos n \omega_{0}t\, dt$$ $$b_{n} = \frac{2}{T} \int_{d}^{d+t} f(t) \sin n \omega_{0}t\, dt$$

Iniciando el calculo:

$$a_{0} = \frac{2}{4} \int_{-2}^{2}t\,dt = \frac{1}{2} \bigg[\frac{t^2}{2}\bigg]_{-2}^{2} = \frac{1}{2} \bigg[\frac{(-2)^2}{2} - \frac{2^2}{2}\bigg] = \frac{1}{2} \big[0\big] = 0$$
$$ a_{n} = \frac{2}{4} \int_{-2}^{2}t \cos n \frac{\pi}{2} t\,dt$$

Tabla:

$$+$$ $$t$$ $$\cos n \frac{\pi}{2} t$$
$$-$$ $$1$$ $$\frac{\sin n \frac{\pi}{2} t }{n\frac{\pi}{2}}$$
$$$$ $$0$$ $$\frac{1}{n\frac{\pi}{2}}\bigg[\frac{-\cos n \frac{\pi}{2}t}{n\frac{\pi}{2}}\bigg]$$
$$a_{n} = \frac{1}{2} \bigg[\frac{t\sin n \frac{\pi}{2} t }{n\frac{\pi}{2}} + \frac{1}{n\frac{\pi}{2}}\bigg[\frac{\cos n \frac{\pi}{2}t}{n\frac{\pi}{2}}\bigg]\bigg]_{-2}^{2}$$ $$ a_{n} = \frac{1}{2} \Bigg[\Bigg(\frac{2\sin n\frac{\pi}{2}2}{n\frac{\pi}{2}} + \frac{1}{n\frac{\pi}{2}}\bigg[\frac{\cos n \frac{\pi}{2}2}{n\frac{\pi}{2}}\bigg]\Bigg) - \Bigg(\frac{-2\sin n\frac{\pi}{2}-2}{n\frac{\pi}{2}} + \frac{1}{n\frac{\pi}{2}}\bigg[\frac{\cos n \frac{\pi}{2}-2}{n\frac{\pi}{2}}\bigg]\Bigg)\Bigg] $$ $$ a_{n} = \frac{1}{2} \Bigg[\Bigg(\frac{4\sin n\pi}{n\pi} + \frac{4 \cos n \pi}{n^2\pi^2}\Bigg) - \Bigg(\frac{-4\sin -n\pi}{n\pi} +\frac{4\cos -n\pi} {n^2\pi^2}\Bigg)\Bigg] $$ $$ a_{n} = \frac{1}{2} \Bigg[\Bigg(0 + \frac{4 \cos n \pi}{n^2\pi^2}\Bigg) - \Bigg(0 +\frac{4\cos -n\pi} {n^2\pi^2}\Bigg)\Bigg] $$ $$ a_{n} = \frac{1}{2} \Bigg[\frac{4 \cos n \pi}{n^2\pi^2} -\frac{4\cos -n\pi} {n^2\pi^2}\Bigg] = 0$$
$$ b_{n} = \frac{2}{4} \int_{-2}^{2}t \sin n \frac{\pi}{2} t\,dt$$

Tabla:

$$+$$ $$t$$ $$\sin n \frac{\pi}{2} t$$
$$-$$ $$1$$ $$\frac{- \cos n \frac{\pi}{2} t }{n\frac{\pi}{2}}$$
$$$$ $$0$$ $$-\frac{1}{n\frac{\pi}{2}}\bigg[\frac{\sin n \frac{\pi}{2}t}{n\frac{\pi}{2}}\bigg]$$
$$b_{n} = \frac{1}{2}\bigg[\frac{-2t \cos n \frac{\pi}{2}t}{n\pi} + \frac{4\sin n \frac{\pi}{2}t}{n^2 \pi^2}\bigg]_{-2}^{2}$$ $$b_{n} = \frac{1}{2}\Bigg[\Bigg(\frac{-2(2) \cos n \frac{\pi(2)}{2}}{n\pi} + \frac{4\sin n \frac{\pi(2)}{2}}{n^2 \pi^2}\Bigg) - \Bigg(\frac{-2(-2) \cos n \frac{\pi(-2)}{2}}{n\pi} + \frac{4\sin n \frac{\pi(-2)}{2}}{n^2 \pi^2}\Bigg)\Bigg]$$ $$b_{n} = \frac{1}{2}\Bigg[\Bigg(\frac{-4 \cos n \pi}{n\pi} + \frac{4\sin n \pi}{n^2 \pi^2}\Bigg) - \Bigg(\frac{4 \cos -n\pi }{n\pi} + \frac{4\sin -n\pi}{n^2 \pi^2}\Bigg)\Bigg]$$ $$b_{n} = \frac{1}{2}\Bigg[\Bigg(\frac{-4 \cos n \pi}{n\pi} +0\Bigg) - \Bigg(\frac{4 \cos -n\pi }{n\pi} + 0\Bigg)\Bigg]$$ $$b_{n} = \frac{1}{2}\Bigg[\frac{-4 \cos n \pi}{n\pi} - \frac{-4 \cos - n \pi}{n\pi}\Bigg]$$ $$b_{n} = \frac{1}{2}\Bigg[\frac{-4 (-1)^n)}{n\pi} - \frac{-4 (-1)^n}{n\pi}\Bigg]$$ $$b_{n} = \frac{1}{2}\Bigg[\frac{-8 (-1)^n}{n\pi}\Bigg]$$ $$b_{n} = \frac{-8 (-1)^n}{2n\pi} = \frac{-4 (-1)^n}{n\pi} = \frac{4 (-1)^{n+1}}{n\pi} $$

Coeficientes obtenidos:

$$ \begin{cases} a_{0} = 0 \\ a_{n} = 0 \\ b_{n} = \frac{4 (-1)^{n+1}}{n\pi} \end{cases} $$

Por lo tanto, la serie es:

$$f(t)= 4\displaystyle\sum_{n=1}^\infty \frac{ (-1)^{n+1}}{n\pi}\sin{\frac{n\pi}{2}t}$$

Aproximación de orden 3:

$$f(t) = 4\bigg(\pi \sin \frac{\pi}{2}t - \frac{1}{2\pi} \sin \pi t + \frac{1}{3\pi} \sin \frac{3\pi}{2}t\bigg)$$
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Ahora calcularemos los coeficientes para la serie Compleja:

$$f(t)= C_{0} + \sum_{\substack{n=-\infty\\n\ne 0}}^\infty C_{n}e^{in\omega_{0}t}$$

Los coeficientes:

$$C_{0} = \frac{1}{T} \int_{d}^{d+T} f(t) \, dt$$ $$C_{n} = \frac{1}{T} \int_{d}^{d+T} f(t)e^{-in \omega_{0} t} \, dt$$

Calculando:

$$C_{0} = \frac{1}{4} \int_{-2}^{2} t\,dt = \frac{1}{4}\Bigg[\frac{t^2}{2}\Bigg]_{-2}^{2} = 0$$
$$C_{n} = \frac{1}{4} \int_{-2}^{2} t e^{-\frac{i n \pi }{2} t} \, dt$$

Tabla:

$$+$$ $$t$$ $$e^{-\frac{i n \pi }{2} t}$$
$$-$$ $$1$$ $$-\frac{e^{-\frac{i n \pi }{2} t}}{\frac{i n \pi }{2}}$$
$$$$ $$0$$ $$-\frac{e^{-\frac{i n \pi }{2} t}}{\frac{ n^2 \pi^2 }{4}}$$
$$C_{n} = \frac{1}{4} \Bigg[-\frac{te^{-\frac{i n \pi }{2} t}}{\frac{i n \pi }{2}} + \frac{e^{-\frac{i n \pi }{2} t}}{\frac{ n^2 \pi^2 }{4}}\Bigg]_{-2}^{2}$$ $$C_{n} = \frac{1}{4} \Bigg[\Bigg(-\frac{(2)e^{-\frac{i n \pi }{2} (2)}}{\frac{i n \pi }{2}} + \frac{e^{-\frac{i n \pi }{2} (2)}}{\frac{ n^2 \pi^2 }{4}}\Bigg) - \Bigg(-\frac{(-2)e^{-\frac{i n \pi }{2} (-2)}}{\frac{i n \pi }{2}} + \frac{e^{-\frac{i n \pi }{2} (-2)}}{\frac{ n^2 \pi^2 }{4}}\Bigg)\Bigg]$$ $$C_{n} = \frac{1}{4} \Bigg[\Bigg(-\frac{4e^{-i n \pi}}{i n \pi} + \frac{4e^{-i n \pi}}{n^2 \pi^2}\Bigg) - \Bigg(\frac{4e^{i n \pi}}{i n \pi} + \frac{4e^{i n \pi}}{ n^2 \pi^2}\Bigg)\Bigg]$$ $$C_{n} = \frac{1}{4} \Bigg[-\frac{4e^{-i n \pi}}{i n \pi} + \frac{4e^{-i n \pi}}{n^2 \pi^2} - \frac{4e^{i n \pi}}{i n \pi} - \frac{4e^{i n \pi}}{ n^2 \pi^2}\Bigg]$$ $$C_{n} = \frac{1}{4} \Bigg[-\frac{4(-1)^n}{i n \pi} + \frac{4(-1)^n}{n^2 \pi^2} - \frac{4(-1)^n}{i n \pi} - \frac{4(-1)^n}{ n^2 \pi^2}\Bigg]$$ $$C_{n} = \frac{1}{4} \Bigg[-\frac{4(-1)^n}{i n \pi} - \frac{4(-1)^n}{i n \pi} \Bigg]$$ $$C_{n} = \frac{1}{4} \Bigg[- \frac{8(-1)^n}{i n \pi} \Bigg]$$ $$C_{n} = - \frac{8(-1)^n}{4i n \pi} = \frac{-2(-1)^n}{in\pi} = \frac{2(-1)^{n+1}}{in\pi}$$

Por lo tanto, la serie compleja es:

$$f(t)= 2\sum_{\substack{n=-\infty\\n\ne 0}}^\infty \frac{(-1)^{n+1}}{in\pi} \cdot e^{i n \frac{\pi}{2} t }$$

Calculo de Potencia de Orden 2:

$$P= {\lvert C_{0} \rvert }^2 + 2 \sum_{n=1}^2 {\lvert C_{n} \rvert }^2$$ $$P= {\lvert C_{0} \rvert }^2 + 2{\lvert C_{1} \rvert }^2 + 2{\lvert C_{2} \rvert }^2$$ $$C_{n} = \frac{2(-1)^{n+1}}{in\pi}$$

Tabla:

$$n$$ $$C_{n}$$ $$\lvert C_{n} \rvert$$ $$Amplitud$$ $${\lvert C_{n} \rvert}^2$$ $$Potencia$$ $$\sphericalangle C_{n}$$ $$Fase$$
$$0$$ $$0$$ $$0$$ $$0$$ $$2\pi$$
$$1$$ $$\frac{-2i}{\pi}$$ $$\frac{2}{\pi}$$ $$\frac{4}{{\pi}^2}$$ $$\frac{3 \pi }{2}$$
$$2$$ $$\frac{i}{\pi}$$ $$\frac{1}{\pi}$$ $$\frac{1}{{\pi}^2}$$ $$\frac{\pi}{2}$$
$$3$$ $$\frac{-2i}{3\pi}$$ $$\frac{2}{3\pi}$$ $$\frac{4}{9{\pi}^2}$$ $$\frac{3\pi}{2}$$

Calculo de la Potencia:

$$ P \approx 2\Bigg( \frac{4}{{\pi}^2} \Bigg) + 2\Bigg( \frac{1}{{\pi}^2}\Bigg) \approx \frac{1}{{\pi}^2} \Bigg( 8 +2 \Bigg)$$ $$ \approx 1.0132 [W] (Watts)$$

Espectro de Potencia & Fase con 3 armonicos:

$$n \omega_{0} = \frac{n}{2 \pi} f_{0} [Hz]$$
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